x^2=-7x+12=0

Solution for x^2=-7x+12=0 equation:

x^2=-7x+12=0

We move all terms to the left:

x^2-(-7x+12)=0

We get rid of parentheses

x^2+7x-12=0

a = 1; b = 7; c = -12;
Δ = b2-4ac
Δ = 72-4·1·(-12)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{97}}{2*1}=\frac{-7-\sqrt{97}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{97}}{2*1}=\frac{-7+\sqrt{97}}{2}
$